Sequels in SQL challenge – «Քան» ակադեմիայի աջակցության կենտրոն

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Sandra Hamilton

April 29, 2020 10:24

0

I don't seem to be able to complete the challenge successfully even though I have achieved the result they asked for. What am I doing wrong?

My code:

SELECT movies.title, sequels.title as sequel_title
FROM movies
LEFT OUTER JOIN movies sequels
ON movies.sequel_id = sequels.id;

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2 comments

SweetSourBlueberry

May 06, 2020 11:25
0

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Sandra, unfortunately, we can't help you if you don't give us the name, or object of the challenge. After you put a comment here, I'll see what I can do to help!
Andrew Grogan

February 17, 2021 15:14
3

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Hey I have the answer right here for you

SELECT movies.title AS movies_title, sequel.title AS sequel_titles
FROM movies
LEFT OUTER JOIN movies sequel
ON movies.sequel_id = sequel.id;

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