Trig Identity help

I really can't figure out how they got this last equivalent. Can someone help?

I really can't figure out how they got this last equivalent. Can someone help?
Apply the double-angle identity for sine:
sin(theta)cos(theta) = (1/2) * 2sin(theta)cos(theta) = (1/2)sin(2theta).
So, sin(theta)cos(theta) is indeed equal to (1/2)sin(2theta).
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