parth g

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2. Computing Platform Community Discussions
3. Help me please!! Then you can use COUNT with GROUP BY to show the number of students with each of those grades.

SELECT name, number_grade, Round(fraction_completed*100)as percent_completed from student_grades ;SELECT count(name), number_grade,CASE WHEN number_grade>90 THEN "A"WHEN number_grade>80 THEN "B"WHE...