Thermochemistry Problem: Heat Capacity of Lead

Can anyone help me confirm if my answer/process is correct? 

The question asks: Calculate the heat capacity in joules and in calories per degree, of 1.00 oz of lead.

First, I converted the 1.00 oz to grams, and got 28.35 g.

Next, I multiplied 28.35 g by 0.159 J/gC because I found that 0.159 J/gC is the specific heat of lead: https://owl.oit.umass.edu/departments/Chemistry/appendix/SpecificHeats.html

On multiplying that, I got 4.51 J/C. 

To convert the J/C to calories, I divided 4.51 J/C by 4.184,and got 1.08 cal C^-1

The solutions manual to the question says otherwise (shown below):

28.4 g * 0.129 J/g C = 3.66 J/C

I'm unfortunately, confused. Is the specific heat capacity of lead 0.129 J/gC or 0.159 J/gC? Thank you for your patience!