Gradient of a vector – Khan Academy Help Center - Turkish (BETA)

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88

31 Ekim 2017 14:49
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2

Hey Khan Academy,

It would be great if you expanded the gradient knowledge with the Gradient of a Vector!

I would much appreciate such addition.

Yeni gönderi

1 yorum

Alex(Prometheus)

31 Ekim 2017 14:54
1

Yorum işlemleri Permalink
Yeah, I think that would be awesome!

Gönderi yorumlara kapalı.