Como podemos ajudar?

Arnav Chauhan

Arnav Chauhan comentou, 8 de agosto de 2017 14:13
Yes, f(x) = 2x/(x^2-1) is not invertible. But restricting it's domain to (-1,1) would allow us to conclude that the inverse of the function f is 1/y.(1 - sqrt(1+x^2)) and the graph of the same is a...
Arnav Chauhan comentou, 8 de agosto de 2017 11:28
I just got the answer of this, it's x = 1/y.(+/- sqrt(-y^2+1) + 1) But according to this equation, y=0 is undefined but f(0) = 0. Why the inverse not giving the correct answer? (The inverse matches...
Arnav Chauhan criou uma publicação, 8 de agosto de 2017 06:36
Inverse Fucntions
Respondida

How do I, algebraically, find the inverse function to f(x) = 2x/(x^2-1) ?
1. Comunidade
2. Study Group
Arnav Chauhan criou uma publicação, 21 de julho de 2017 14:57
Rational Functions
Respondida

Say x^6 - 64 = f(x). The domain of this function is (-infty,infty). But f(x)/(x-2) is a continuous graph and does not have any breaks at x=2. Why is this? If it is because it is divisible by (x-2...
1. Comunidade
2. Study Group
Arnav Chauhan criou uma publicação, 28 de junho de 2017 08:45
Natural Numbers. No 0, then how come 10?
Respondida

If natural numbers are defined to NOT include 0. Why do they include numbers with digits 0??
1. Comunidade
2. Study Group