Probability combinations question

Hi in a video on combinations https://youtu.be/DIjlllgq3dc

this is the problem

To win a particular lottery game, a player chooses 4 numbers from 1 to 69. Each number can only be chosen once. If all 4 number match the 4 winning numbers, regardless of order, the player wins. What is the probability that the winning numbers are 3, 15, 46, and 49?

The solution is given as the chance of getting 3, 15, 46, and 49 divided by the total number of possibilities of 4 numbers.

1 in 487,635

But - it is not clear that 3, 15, 46, and 49 have to be in that order?

Shouldn't the answer be 4! in 487635? As those 4 winning numbers could come in any order?

Thanks.