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sivathmigak

2 november 2017 21:47

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Calculate the mass of CaCo3 that must be decomposed to produce 500.0g of CaO. Equation for the reaction is CaCO3(s) --> CaO(s)+CO2(g)

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aldajabana5

4 november 2017 12:34
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To solve this you need molar weights for CaO&CaCO3
Mw CaO=56.077g/mol and Mw CaCO3=100.086g/mol
Using stochiometry:
500.0gCaO * (1mol CaO/56.077gCaO) * (1mol CaCO3/1mol CaO) * (100.086g CaCO3/1mol CaCO3)=892.4 g of CaCO3

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