Honors chemistry problem

Yes, it is possible... Say I have 32 g of oxygen gas(O2) and 32 g of methane(CH4) in a container. That means, I have 1 mole of O2(as 32 g is the mass of one mole of diatomic oxygen) and 2 moles of Ch4(as 16g is the mass of one mole of CH4; so 32 g of CH4 has 2 moles of CH4).

So, the mole-fraction of O2 is [1/(1+2)] = 1/3

and that of CH4 is [2/(1+2)] = 2/3

Multiplying each mole-fraction by the total pressure P inside the container, we get P(oxygen) = (P/3) and P(methane) = (2P/3)

Thus the partial pressure of methane is twice as much as that of oxygen, though equal masses of both gases exist in the container...