Vinicius Raphael

My resolution after a little bit of research was the one below STEP 1 SELECT name, number_grade, ROUND(fraction_completed * 100) as percent_completedFROM student_grades; STEP 2 (Any coma or AS plac...

1. Communauté
2. Computing Platform Community Discussions
3. Help me please!! Then you can use COUNT with GROUP BY to show the number of students with each of those grades.