Help with a trig problem
I am having trouble with finding all the solutions to 9sintheta-1=7sintheta I worked this through until it became 2sin = 1 and now I am stuck
I am having trouble with finding all the solutions to 9sintheta-1=7sintheta I worked this through until it became 2sin = 1 and now I am stuck
Could you please specify if you mean 9sin(theta-1) = 7 or 9sin(theta)-1 = 7?
You had:
9sin(θ) - 1 = 7sin(θ)
Subtract 7sin(θ) from both sides:
2sin(θ) - 1 = 0
Now you got:
2sin(θ) = 1
Divide both sides by 2:
sin(θ) = 1/2
Now you’re asking: what values of θ make sin(θ) = 1/2?
Here’s the key bit — we look at the unit circle or our sine knowledge.
Sine equals 1/2 at two standard angles:
θ = 30° (or π/6 radians)
and its twin in Quadrant II: θ = 150° (or 5π/6 radians)
So your final answers are:
θ = 30° and θ = 150°
or
θ = π/6 and 5π/6, if you're using radians.
I hope this was the answer you were looking for
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