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Arnav Chauhan

Arnav Chauhan hizo un comentario, 8 de agosto de 2017 14:13
Yes, f(x) = 2x/(x^2-1) is not invertible. But restricting it's domain to (-1,1) would allow us to conclude that the inverse of the function f is 1/y.(1 - sqrt(1+x^2)) and the graph of the same is a...
Arnav Chauhan hizo un comentario, 8 de agosto de 2017 11:28
I just got the answer of this, it's x = 1/y.(+/- sqrt(-y^2+1) + 1) But according to this equation, y=0 is undefined but f(0) = 0. Why the inverse not giving the correct answer? (The inverse matches...
Arnav Chauhan creó una publicación, 8 de agosto de 2017 06:36
Inverse Fucntions
Respondida

How do I, algebraically, find the inverse function to f(x) = 2x/(x^2-1) ?
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Arnav Chauhan creó una publicación, 21 de julio de 2017 14:57
Rational Functions
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Say x^6 - 64 = f(x). The domain of this function is (-infty,infty). But f(x)/(x-2) is a continuous graph and does not have any breaks at x=2. Why is this? If it is because it is divisible by (x-2...
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Arnav Chauhan creó una publicación, 28 de junio de 2017 08:45
Natural Numbers. No 0, then how come 10?
Respondida

If natural numbers are defined to NOT include 0. Why do they include numbers with digits 0??
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