
20leunge
-
I think to make it different from the first time you learned the subject is to make acceleration much faster than the first time you completed it. It would make it so you don't have to spend too mu...
-
This is a long post, so I've italicized questions and bolded answers. Let me know if there are any mistakes. The first thing to realize is that we are dealing with finite arithmetic series, that is...
-
Khan Academy isn't an actual school, so I wouldn't think so.
-
- Community
- Feature Requests and General Site Feedback
- Changing Mastery To A Passing Grade Level (75-100%) Instead of Just 100%
It's called mastery for a reason, is it not? That was the whole point of the mastery system, to get away from the passing grade system, and make sure students really learned what they learned. A le...
-
Just looking at the partial derivative with respect to x, I believe the chain rule is being applied to Q, and then to R along with the product rule. The chain rule is being used because z is itself...
-
What I did was I skipped this part and continued learning until I finished the combinatorics section from Precalculus. Then, I went back and learned it. It's not exactly a recurring topic throughou...
-
- Community
- News and Updates from Khan Academy
- Content Update: September 2018 (Music, History, Physics, and more!)
Can the new content for physics for India be found in the general physics subject as well?
-
I think Okapi is right. You will probably need to learn calculus to find the instantaneous speed
-
I don't think all the steps I used can be found on Khan Academy
-
I disagree. There are infinitely more answers. For example, if you use u=(pi) , the equation also works, where both sides equal 0. All possible angles for u can be represented as the following, whe...
-
Total activity 151
-
Last activity
-
Member since
-
Following 0 users
-
Followed by 1 user
-
Votes 50
-
Subscriptions 49
-
Total activity 151
-
Last activity
-
Member since
-
Following 0 users
-
Followed by 1 user
-
Votes 50
-
Subscriptions 49