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# 20leunge

• I had the same problem. If you want, you can just skip the section and move on until you learn combinatorics in precalculus, and then go back to this section. You could also learn them right now by...

• I don't know if they will add this, but in the meantime, perhaps you could go through the science content and align it with the curriculum or syllabus your son's school has.

• Do you mean having to click on the box to be able to type in your answer? If you don't want to use your mouse, maybe using the "tab" button will work.

• I think this is a great idea. Maybe the hidden version can hide the code and prevent others from bringing up the source code in case the creator doesn't want spin offs to maximize privacy. Or, user...

• You are taking the cube root of the expression (3x-5)^3. That means you are finding the expression you need to multiply by itself 3 times to get (3x-5)^3, which is just (3x-5). 2(3x-5) is just 2 ti...

• Since you're multiplying them, you have to add the exponents (the images don't work by the way). We get each fraction into equivalent forms with common denominators: (3/4) = (9/12) and (1/3) = (4/1...

• According to https://blog.prepscholar.com/whats-the-difference-between-ap-physics-1-2-and-c, you probably only need math through Algebra II to understand what Khan Academy offers. I don't think KA ...

• Here's how I see it. Let x represent the time Rob intended to spend on the project. However, he spent 100% of that times AND 25% more, so 125% of the planned time. So the time Rob actually spent wa...

• RowanH: In general, |x|+|y| ≠ |x+y|. Consider x = 1, y = -1. |x|+|y| = 2 |x+y| = 0.  So. |x|+|y| ≠ |x+y| because 2 ≠ 0. zineb.aj: I'm not sure why you wouldn't want to remove the absolute value sym...

• First, solve x^2=a^2. Take the plus and minus square root of both sides. The negative root is needed because when that is squared on both sides, you still get back the original equation. ==> x=a, x...

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