Trig Identity help – Khan Academy Help Center

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douglas allred

June 08, 2023 09:25

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I really can't figure out how they got this last equivalent. Can someone help?

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yoon_koh

June 17, 2023 11:19
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Apply the double-angle identity for sine:

sin(theta)cos(theta) = (1/2) * 2sin(theta)cos(theta) = (1/2)sin(2theta).

So, sin(theta)cos(theta) is indeed equal to (1/2)sin(2theta).

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