Limiting Reactant and percent yield

I tried my best, because I haven't done limiting reactants or stoichiometry in a couple months, so I'm slightly rusty. Also, the dihydrate part threw me off, but I will just give you the answers I calculated. The first answer is based without the dihydrate and the second with the molar mass of two molecules of water counted into the copper chloride's molar mass. I apologize for any mistakes, it was the best I could remember, and it's kind of hard to find helpers in topics besides math, so I wanted to help to the best of my knowledge.

Limiting Reactant: Copper Chloride --> CuCl2

Final Result (without dihydrate): 0.026 mol Cu --> 1.7 grams Cu

Final Result (with dihydrate): 0.021 mol Cu --> 1.3 grams Cu

Reaction: 2Al + 3CuCl_2 ----> 2AlCl_3 + 3Cu

Comment if you want me to show my work.