newton's law

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Princess Maithani

5. oktober 2016 15:10

A man pushes a crate of mass 45 kg across a horizontal floor with a horizontal force of 475 N. If the coefficient of kinetic friction between the crate and the floor is 0.64, what is the magnitude of the acceleration of the block in units of m/s²?

(the equation for the friction force is F_F = μ_kN)

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Princess Maithani

5. oktober 2016 16:21
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can anybody help me with this pleaasssse :((((
William Merkel

8. oktober 2016 02:35
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Remember there are two forces in action: the man pushing the block horizontally and 2. an opposite force acting against it. The acceleration is the result of the difference of these two forces.

Step one: find the force of the Friction: what is the Normal force (that is your wieght due to gravity) of the crate and multiply that by the coefficient of friction. Ff=UkN

then take the force for the man 475N then subtract the friction force.

Once that is done you still have to find the acceleration. Hint F=ma

This is only a hint, the numbers you need to fill in. I hope this clears it up without giving you the answer.

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newton's law

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