parth g

1. Общност
2. Computing Platform Community Discussions
3. Help me please!! Then you can use COUNT with GROUP BY to show the number of students with each of those grades.

SELECT name, number_grade, Round(fraction_completed*100)as percent_completed from student_grades ;SELECT count(name), number_grade,CASE WHEN number_grade>90 THEN "A"WHEN number_grade>80 THEN "B"WHE...