Chemistry - Dilution & molarity

One of the questions I just did had an explanation that didn't make sense. Please see the picture and look at step 2 where the number of moles of OH- is calculated by multiplying the 0.352 moles of Ba(OH)2 by 2 mol OH- over 1 mol Ba(OH)2 which gives a final molarity that is of course double, which doesn't make sense to me - how can the molarity of the OH- ions be higher than the molarity of the entire molecule? Surely because the total number of "components" of the molecule is 3 (1 Ba2+ & 2 OH-) the ration used to multiply should be 2/3 and not 2/1 ?

I must be thinking about something incorrectly...

Thanks

Elio